tentukan luas dan keliling bangun berikut!
[tex]as = \sqrt{ {c}^{2} - {t}^{2} } = \sqrt{ {10}^{2} - {8}^{2} } \\ \sqrt{100 - 64} = \sqrt{36} = 6 \\ a = 6 + 12 = 18 \\ \\ luas \: trapesium \\ \frac{1}{2} t(a + b) \\ \frac{1}{2} .8(18 + 12) \\ 4(30) \\ 120 \: {cm}^{2} \\ \\ keliling \: trapesium \\ a + b + c + d \\ 18 + 12 + 8 + 10 \\ 48 \: cm[/tex]
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